4^-5/2^-3=8^-x

Solution for 4^-5/2^-3=8^-x equation:

4^-5/2^-3=8^-x

We move all terms to the left:

4^-5/2^-3-(8^-x)=0

We add all the numbers together, and all the variables

-(8^-x)-5/2^=0

We get rid of parentheses

x-8^-5/2^=0

We multiply all the terms by the denominator


x*2^-5-8^*2^=0

We add all the numbers together, and all the variables

x*2^=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$